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4. Inverse Square Law

Objectives


  1. To understand what the inverse square law is
  2. To Understand how the inverse square law arises

4.1 Spread of sound energy in the freefield

When we are thinking of a sound source in a free-field (i.e. nothing for the sound to hit as it travels away from the source) we can think of the sound waves as expanding like the surface of a balloon being blown up. As it travels outwards the surface of the balloon gets bigger and bigger - the sound energy is spread out over a larger and larger area. As the radius of the balloon doubles, the area goes up four-fold. Remember, the area of a sphere is given by:

(4.1)

So if r goes up by a factor of 2, then the area increases by a factor of 22 or 4. This is demonstrated in figure 4.1 below.

 

Fig. 4.1: From a point source in free-field sound radiates outwards in all directions. We assume that at a given (R) from the source a certain amount of sound energy flows through area (A). If we now double the distance from the source, the same amount of energy now flows through an area 4 times the size - i.e. for an area of the same size of A, only a quarter of the sound energy passes through it

4.2 Decibels and the inverse square law

If our original sound source has a power given by P then this is this is spread out over the surface of a sphere, then the expression for sound intensity at a given point on that sphere becomes:

(4.2)

So for example, if we have a sound source with a power of 1 W, we measure the intensity at 0.5m from the source and then measure again at a distance of 1m. How much does the sound intensity level drop between the two measurements.

Remember from (3.7) that the ratio of two intensities can be expressed as:

The expression within the brackets can be rearranged - if you want to divide by a fraction you can turn it upside down and multiply by it, then we can simplify:


We might have expected this, we have the same sound power, but it passes through 4 times the area, so for a given area unit of area the sound intensity must have decreased by a factor of 4.

We can now think of this decrease in sound intensity in terms of decibels:


So what does this mean in real life? Basically, if we are in a situation where the inverse square law is obeyed, as we double the distance from a sound source, the sound intensity decreases by 6 dB. This is referred to as the inverse square law.

 

Reflection

Example  1 - Sound power and intensity

Suppose a single point sound source has a power of 1W and it radiates out evenly in all directions - what is the intensity 10m from the source?

Reflection

Example 2 -  Intensity and dB SPL

If we assume a plane wave, what is the sound pressure level measured in example 1?

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