Week 10 Tutorial Solutions
- The rule does not make sense at the constant sequence
because no is equal to 0. Define at this point to take the value
and think of the odometer resetting.
- because if then and if it must have been the case that and therefore .
- Let be the coin measure. Thus and . If is invariant then
which is impossible unless .
- Since and we have
and from
we see it is an eigenfunction of eigenvalue .
- Take
which are eigenfunctions of with eigenvalues , , and respectively. As their eigenvalues are distinct they are linearly independent.
- From
we see that and span the same subspace.
- We can write
by some linear algebra.
- The collection of cylinders (including the empty set) is a π-system so it suffices to check that for every cylinder . But for every cylinder its inverse image under is another cylinder of the same length, defined by the symbols that odometrically precede . With respect to the fair coin measure, all cylinders of length have the same measure. Thus is an invariant measure for .
- Mimicking the answer to 7 with longer cylinders, we can find for every with and for some an eigenfunction of with eigenvalue . As, for every cylinder set , we can write as a linear combination of such eigenfunctions, we can conclude that the eigenfunctions span . There are therefore no other eigenvalues of and has discrete spectrum.